Indicate which property is illustrated in Step 5.

Step 1 9 + 10x - 9 - 4x + 5 = 9 + (10x - 9) - 4x + 5
Step 2 = 9 + (-9 + 10x) - 4x + 5
Step 3 = [9 + (-9)] + (10x - 4x) + 5
Step 4 = 0 + (10x - 4x) + 5
Step 5 = (10x - 4x) + 5
Step 6 = (10 - 4)x + 5
Step 7 = 6x + 5

commutative
additive inverse
additive identity
distributive

Question

Indicate which property is illustrated in Step 5.

Step 1	9 + 10x - 9 - 4x + 5	=	9 + (10x - 9) - 4x + 5
Step 2		=	9 + (-9 + 10x) - 4x + 5
Step 3		=	[9 + (-9)] + (10x - 4x) + 5
Step 4		=	0 + (10x - 4x) + 5
Step 5		=	(10x - 4x) + 5
Step 6		=	(10 - 4)x + 5
Step 7		=	6x + 5

    commutative
    additive inverse
    additive identity
    distributive

directrix · Answer

The question is how to get from:

0 + (10x - 4x) + 5  to  (10x - 4x) + 5

anonymous · Answer

IM confused @Directrix

directrix · Answer

What was added to give the same "identical" expression back?

directrix · Answer

These are almost the same except that the left one has a zero with it:

0 + (10x - 4x) + 5 to (10x - 4x) + 5

directrix · Answer

Which option above has an "identity" in it?