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Geometry 16 Online
OpenStudy (anonymous):

Look at the figure shown below.

OpenStudy (anonymous):

OpenStudy (anonymous):

Nora is writing statements as shown to prove that if segment ST is parallel to segment RQ, then x = 45.

OpenStudy (anonymous):

OpenStudy (anonymous):

Which equation can she use as statement 5?

OpenStudy (anonymous):

Select one: a. 60:x = 48:(48 + 36) b. 60 + x = 48 + 36 c. 60 - x = 48 - 36 d. 60:(60+x) = 48:(48 + 36)

ganeshie8 (ganeshie8):

where weru stuck ?

ganeshie8 (ganeshie8):

she has proved the triangles are similar, so u just have to setup an useful proportion

OpenStudy (anonymous):

I thought IT was A but it seems that I did something wrong

Directrix (directrix):

It is not A.

OpenStudy (anonymous):

Yea I think I got confused with D also

Directrix (directrix):

Remember: x is not a side of a triangle in this scenario.

OpenStudy (anonymous):

So its between B and C right

Directrix (directrix):

No, it is not >>>So its between B and C right @Edge

OpenStudy (anonymous):

ohh I got the answer already

Directrix (directrix):

@Edge I hope you went with D here. >>> ohh I got the answer already

OpenStudy (anonymous):

yea I did

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