Any help ? please.
Simplify the expression.
(3+2i)(4-i)

Question

Any help ? please.
Simplify the expression.
(3+2i)(4-i)

yttrium · Answer

FOIL.

yttrium · Answer

Do you know it?

hba · Answer

Also ya need to know that

i^2=-1

timaashorty · Answer

yttrium, can please you show me step by step ?

yttrium · Answer

We have (3+2i)(4-i)
FOIL is method we are using to expand binomials. It means First terms, Outer Terms, Inner Terms and Last terms.
Applying that we will have:
(3*4)+(3*(-i))+(2i*4)+(2i*(-i))
Which is equal to:
12-3i+8i-2i^2 (and we know that fact that i^2 = -1)
Hence,
12+5i-2(-1)
12+5i+2
14+5i --> Final answer.

yttrium · Answer

Just tell me if you still don't get what FOIL method is.

anonymous · Answer

using wolframalpha, you were right Yttrium :D

anonymous · Answer

14 + 5i is (3+2i)(4-i) simplified ^_^

timaashorty · Answer

Thank you so much! I kinda understand the foil method, it's just im a bit confused in this one! but now i got it !

yttrium · Answer

You sure?

timaashorty · Answer

Can you help me with one more ?

timaashorty · Answer

and char what is that, that you use ?

yttrium · Answer

Of course. But I think you better post it as a new question. So we don't need to scroll longer.

anonymous · Answer

timaa, it helps with problems like these :D http://www.wolframalpha.com/input/?i=%283%2B2i%29%284-i%29&dataset= <-- see? ^_^

anonymous · Answer

even shows ya step by step :D

timaashorty · Answer

I'll check that wensite Lola, ^.^

anonymous · Answer

okay timaa :D take care <3 ^_^