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How to simplify log a^7 + 4log a^3 ?
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\[\log_{a ^{7}} +4 \log_{a ^{3}} \]
remember the 3 log rules. \[\log(a^7) + \log([a^3]^4) = \log(a^7) + \log(a^{12}) = \log(a^7a^{12}) = \log(a^{19}) = 19\log(a)\]
Are you sure of this \[ 4\log_{a ^{3}} = \log_{a ^{12}} \] ? I thought it's equals to \[\log_{a ^{81}} \] isnt it ?
There is a difference between (a^3)^4 and a^(3^4)
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