Question

How do I solve x^2-6 x +5 >0 ?

Answer 1

x^2-6 x +5 >0
(x-5)(x-1) >0
x=5, x=1
because the x^2 is positive, the parabola opens upwards.
therefor, the parabola is greater than 0 at {xIx<1, or x>5, xER}