When using a struct to contain a 2D char array, how do you make the size of the array? (using C)

ex.

typedef struct{
char board[][];
}gameBoard;

So I would declare a gameBoard with:
gameBoard board1; correct?

This creates a board, but I don't know how I would create a size for the 2D array. I think you have to use - to get to the 2D array inside, but don't know how to properly size it.

Question

When using a struct to contain a 2D char array, how do you make the size of the array? (using C)

ex.

typedef struct{
      char board[][];
}gameBoard;

So I would declare a gameBoard with:
gameBoard board1; correct?

This creates a board, but I don't know how I would create a size for the 2D array. I think you have to use -> to get to the 2D array inside, but don't know how to properly size it.

anonymous · Answer

i think from what i know, u need to have a constant number with in the arry 
for example char board[100][100], something like that, just to declare the array

e.mccormick · Answer

Are you trying to make it dynamicly sized?

e.mccormick · Answer

http://stackoverflow.com/questions/7221981/how-to-make-a-dynamic-sized-array-in-c

anonymous · Answer

In this case I would want the array to be a different size for each case I make this struct. I want to be able to give it a specific size depending on the case.

anonymous · Answer

Do you know how pointers work?

anonymous · Answer

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