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Solve equation on interval 0<=x<=2pi tan^2x+3/2secx answers are 2pi/3, 4pi/3, need steps to solve please.
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\[\tan^{2}x = \sec^{2}x - 1 \]
\[[\sec^{2}x + \frac{3}{2}secx -1 ] , , x= secx \rightarrow, x^{2} + \frac{3}{2}x -1 \]
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