Question

find the particular solution of

Answer 1

\[x^{2}dy+(xy+y^{2})dx=0 ; y=1 when x=1\]

Answer 2

@hartnn

Answer 3

what kind of diff equation is that?

Answer 4

diffrential equation @RED

Answer 5

I know it is differential equation but what kind of differential equation?

Answer 6

Okay, substitution.

Answer 7

It is Bernoulli's equation, they have a certain way of solve
first divide by dx
then take y^2 to the other side
then divide by x^2y^2
now introduce another variable v=1/y
and complete the rest

Answer 8

Get ready to strain your eyes because I'll be writing fast. I'm about to leave. @RED123url 's method is correct if you already understand it.