Question

Logarithms help

Answer 1

Solve for x:
\[\LARGE \log_5a.\log_ax=2\]
Attempt:
\[\LARGE \frac{1}{\log_a5}.\log_ax=2\]
\[\LARGE x-5=a^2\]
\[\LARGE x=a^2+5\]
OR..
\[\LARGE \frac{x}{5}=a^2\]
\[\LARGE x=5a^2\]

Answer 2

Anyway both are wrong solutions :P what is wrong with them?

Answer 3

ok,
\(\log_BA = \log A / \log B\)
use this for both the terms , and see that log a cancels out.

Answer 4

\[\log_{b} a = \frac{ \log_ca }{ \log_cb }\]
use the reciprocal of this

Answer 5

then its just the matter of using the definition

Answer 6

i think i also used the base change formula..what is wrong in my steps?