Write an equation is slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation. (5,2),y=1/2x-3
If it is perpendicular, the slope will be the opposite reciprocal of the given line. Therefore y=(-2)x + b. Then plug in the points that you know. 2=(-2)5+b 2=-10 + b 12=b
the slope will be the negative reciprocal of 1/2, the equation of the line will be in the same form y=mx+b but you first utilize y-y1=m(x-x1) formula to put the equation of the line into y=mx+b form using the the point given in the question. 5,2. So it becomes y-2=m(negative reciprocal)(x-5).
then solve for y
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