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I have a question if anyone can help me. Thanks! The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 180 cm^2, what is the length of the diagonal?
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Assume Length is L Width = 2L - 1 Area = LW = L(2L - 1) = 180 Solve for L. Find W. Then the diagonal will be sqrt(L^2 + W^2)
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