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e^(0.15t)=25 solve for t
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is this what you do: ln (25) / 0.15
t = ln(25)/0.15 = 21.46
so im right?
what abt this? 2^(t) = 20
log (20) / log(2) ?
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is that right?
@Loser66
@Euler271
Q= ((1.13)^t) / 20
too many comments. not sure what you want me to do
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