How do transform the equation of 6sin2x=5 and find the values of x? 0

Question

How do transform the equation of 6sin2x=5 and find the values of x? 0< or equal to x which is <2pi

anonymous · Answer

i just wanna be awarded as Best Answer!

ranga · Answer

You can divide both sides by 6.  Then take arc sine on both sides and solve for x.

anonymous · Answer

but there would be multiple answers and i don't understand how to find them. the answers the book gives is .49, 1.08, 3.63, 4.22

ranga · Answer

6sin2x = 5
Divide both sides by 6
sin2x = 5/6 = 0.8333
Take arc sine on both sides
2x = arc sine (0.8333)
Use your calculator or online calculator to find the arc sine of 0.83333
I get 0.9851 radians
So 2x = 0.9851
Divide both sides by 2
x = 0.492

So the first choice seems to be the answer.

anonymous · Answer

Thanks!

ranga · Answer

you are welcome.

goformit100 · Answer

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