Question

Related Rates problem! (Calc I)

Answer 1

\[R = pq\]
\[R' = p'q + pq'\]

Answer 2

but which are the pq?

Answer 3

4 posters per day =q'
3$ per day = p'
?

Answer 4

@dumbcow ?

Answer 5

Yes that wil do

Answer 6

p = 3, q = 70

p' = 3, q' = 4

Answer 7

@ganeshie8 is the answer 222?

Answer 8

Yes !

Answer 9

thank you so much!

Answer 10

thats easy to verify also :-
his sales increses 4 each day : today sales are 70+4 = 74
he increased the price by 3$ : today change in price = 3

so change in revenue = 74*3 = 222

Answer 11

np :)

Answer 12

do you think you could also help me out with this one?

Answer 13

@ganeshie8 ?

Answer 14

do the implicit differentiation, and find dx/dt in terms of x and y

Answer 15

\(\large 6x^3 + 5y^3 = xy\)

\(\large 18x^2 x' + 15y^2y' = xy' + x'y\)

Answer 16

you knw \(x, y, y'\), plug them above and solve \(x'\)

Answer 17

oooh i see i see. let me try to get the answer. hold on.

Answer 18

okiee

Answer 19

ummm i got 88 but that's one of my answer choices :/

Answer 20

@ganeshie8

Answer 21

im getting x' = -20/7

Answer 22

yeah that's an answer choice. let me try it again.

Answer 23

ok good

Answer 24

Thank you so much @ganeshie8 ! I got -20/7! I did it right!

Answer 25

glad to hear :)