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Algebra
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he sum of two consecutive odd integers is 28. What are the integers? Which let statement(s) would you use?
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metal...
let n = an integer. two consecutive odd integers would then take the form (2n-1), (2n+1) because we know any integer multiplied by 2 is even 2n mod 2 = 0 and any even integer ±1 is odd (2n ± 1) mod 2 ≠ 0 so solve, (2n-1)+(2n-1)=28
(2n mod 2 here means that 2 divides 2n evenly. there is no remainder. and there is always a remainder when we divide 2n±1 by 2 (it is 1))
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