Question

What are the solutions of the quadratic equation?

2x^2-16x+32=0

Answer 1

Also, I have to show my work

Answer 2

Factor, you get

2(x^2 - 8x + 16) = 0
2(x-4)(x-4) = 0

set each factor equal to 0, you get x = 4.

Answer 3

2x^2-8x-8x+32=2x(x-4)-8(x-4)=(2x-4)(x-4)
x=4 and 2

Answer 4

Okay, so fit those three values into the quadratic formula, which is;