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cos^2*2a-cos^2*4a=sin6a*sin2a
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\(\large cos^2(2a)-cos^2(4a)=sin(6a)sin(2a)\quad ?\)
yea
this is the difference of 2 square quadratic on the left hand side (cos(2a) + cos(4a))(cos(2a) - cos(4a)) so now simplify the binomials... using double angles...
i have tried that no success..
you don't happen to have a screenshot of it?
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its like u wrote it
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