Question

hat are the solutions of the system?
y=x^2-2x-1
y=-2x

Answer 1

-2x = x^2 -2x -1

Answer 2

Put the two x equations equal two each other, so -2x = x^2-2x-1.

Then solve as a quadtratic so x^2-1=0
x = +1 and -1

Put that back into one of the original to get y=-2(1) and y=-2(-1)
So y = -2 or 2

Final answer is (1,-2) and (-1,2)