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Mathematics 8 Online
OpenStudy (anonymous):

The equation of a hyperbola is shown. What are the coordinates of the foci?

OpenStudy (jdoe0001):

\(\bf \cfrac{(x-3)^2}{81}-\cfrac{y^2}{144}=1\implies \cfrac{(x-3)^2}{9^2}-\cfrac{(y-0)^2}{12^2}=1\) where do you think is the center?

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