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Mathematics 22 Online
OpenStudy (anonymous):

OpenStudy (anonymous):

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OpenStudy (anonymous):

@michael0195

OpenStudy (anonymous):

supplementary .-.

OpenStudy (anonymous):

well it's asking me m<RQS=___ m<TQS=___

OpenStudy (anonymous):

like the degree?

OpenStudy (anonymous):

hermmm... im not sure on this one O.o

OpenStudy (raden):

the supplementary angles has sum equal 180 degrees. 21x+4+14x+1=180 solve for x, first

OpenStudy (anonymous):

35x+5=180 145/5 29=x?

OpenStudy (raden):

35x+5=180 subtracted both sides by 5, we get 35x+5-5=180-5 35x =175 then both sides divided by 35 35x/35 = 175/35 x = 5

OpenStudy (anonymous):

Ohh okay. I subtracted 35 from each side

OpenStudy (raden):

now distribute the value of x=5 into m<RQS and m<TQS respectively m<RQS = 21x+4 = 21(5) + 4 = ... degrees m<TQS = 14x+1 = 14(5) + 1 = ... degrees

OpenStudy (anonymous):

109 and 71?

OpenStudy (raden):

correct

OpenStudy (anonymous):

Thank you so much!

OpenStudy (raden):

wlcm

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