Question

Find the real solutions of:
x^4-x^3+2x^2-4x-8=0
please explain and thanks!!!

Answer 1

x^4-2x^3+x^3-2x^2+4x^2-8x+4x-8=0
x^3(x-2)+........
factorise

Answer 2

so you just factor everything like that and set it equal to 0?

Answer 3

or you can say put x=2 in the given eq .we get.0=0
so x-2 is a factor.
divide by 2( synthetic division.)