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OpenStudy (anonymous):

how do you find the derivative of cot^2(sinx)

OpenStudy (anonymous):

well you start from the outside in you find the derivative of the ^2 then cot and finally sin x

OpenStudy (anonymous):

I just dont know how to find the derivative of cot^2

OpenStudy (anonymous):

well its you do it the same way you fine x^2 so it will be 2x so cot^2 will be 2cost()

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