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Mathematics 13 Online
OpenStudy (anonymous):

1. f(x)=1/(x+1); g(x)=x/(x-2) a.f+g

OpenStudy (campbell_st):

wow thats interesting I would have thought it was \[\frac{(x-2) + x(x + 1)}{(x +1)(x -2)}\]

OpenStudy (campbell_st):

simplify the numerator... and you won't get x...

OpenStudy (anonymous):

so the only x will remain?

OpenStudy (campbell_st):

no... the numerator is not x collect the like terms in my expression...

OpenStudy (anonymous):

|dw:1382437056784:dw|

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