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OpenStudy (anonymous):
1. f(x)=1/(x+1); g(x)=x/(x-2) a.f+g
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OpenStudy (campbell_st):
wow thats interesting I would have thought it was \[\frac{(x-2) + x(x + 1)}{(x +1)(x -2)}\]
OpenStudy (campbell_st):
simplify the numerator... and you won't get x...
OpenStudy (anonymous):
so the only x will remain?
OpenStudy (campbell_st):
no... the numerator is not x collect the like terms in my expression...
OpenStudy (anonymous):
|dw:1382437056784:dw|
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