Question

Solve the equation by finding square roots.

3(x-3)^+2=26

Answer 1

@Easyaspi314

Answer 2

start by subtracting 2 both sides

Answer 3

ok then what

Answer 4

then few more steps,
wat do u get when u subtract ?

Answer 5

3(x-3)^=24

Answer 6

then divide 3 both sides

Answer 7

wait the swaure root of 8 is 4 rad 2 ??

Answer 8

sqrt(8) = sqrt(4*2) = 2sqrt(2)

Answer 9

i dont get this one: 5x^+13x=2x^+4

Answer 10

is this a different question.... ?
are we done wid first question ?

Answer 11

ya

Answer 12

may i knw wat did u get as solution ?

Answer 13

cuz there are two solutions, and i think u seem to be missing one

Answer 14

? for the first question i got 3 plus or minus 2 rad 2

Answer 15

okay we're good :)

Answer 16

can u please help me with this next one i have to go

Answer 17

5x^2+13x=2x^2+4

Answer 18

subtract 2x^2 both sides

Answer 19

then complete the square

Answer 20

give it a try

Answer 21

wait so it would be 13/2 and then u take the suare root???

Answer 22

not that simple

Answer 23

before we begin solving,
u sure ur equation is really like this ?
5x^2+13x=2x^2+4

Answer 24

wait no its 13 not 13x

Answer 25

5x^2+13=2x^2+4
like this ?

Answer 26

yes

Answer 27

5x^2+13=2x^2+4

subtract 2x^2 both sides

3x^2 + 13 = 4

subtract 13 both sides

3x^2 = -9

divide 3 both sides

x^2 = -3

Answer 28

then what ?