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Mathematics
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OpenStudy (anonymous):
can someone please help me answer this question?
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OpenStudy (anonymous):
OpenStudy (anonymous):
sorry its upside down...idk how to turn it
OpenStudy (anonymous):
OpenStudy (anonymous):
˙ɔ ɹo 'q 'ɐ ɹəɥʇıə əq plnoʍ ɹəʍsuɐ ɹnoʎ 'ʍoɥʎuɐ ˙ɹəʌo ɹəʍsuɐ ʎɯ dılɟ ʇ,uplnoɔ ı 'ʎɹɹos
OpenStudy (anonymous):
lol how did he do that
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OpenStudy (anonymous):
H4X
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
(Hacks, idiots on the internet refer to it as "H4X" though, the 4 replacing that a in hacks, and the x replacing the cks)
OpenStudy (anonymous):
oh lol ill have to try that sometime just to mess with ppl
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OpenStudy (anonymous):
¡¡¡¡¡¡¡¡¡¡¡əɯosəʍɐ
OpenStudy (anonymous):
¡uʍop əpısdn ƃuıʞlɐʇ unɟ os s,ʇı
OpenStudy (anonymous):
¡¡¡¡¡¡¡¡¡ʇɥƃıɹ ʍouʞ ı lol
OpenStudy (anonymous):
llıʇs pəɹəʍsuɐ uoıʇsənb ɹəɥ spəəu ʎlqɐqoɹd ʎpɐl sıɥʇ
OpenStudy (anonymous):
srry i cant help :(
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OpenStudy (anonymous):
Same, I'm too stupid. :P Good luck lady!
OpenStudy (anonymous):
hahaha its okay
OpenStudy (aakashsudhakar):
I'll help.
51a) f(x) = x^(1/3)
f'(x) = (1/3)(x^(-2/3))
f'(x) = 1/(3x^(2/3))
\[f'(x) = \frac{ 1 }{ 3x^\frac{ 2 }{ 3} }\]
51b) f'(0) = 1/(3(0)^(2/3))
f'(0) = 1/(3(0))
f'(0) = 1/0
f'(0) = UNDEFINED
51c) |dw:1382889020757:dw|
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