Question

Compound fractions?

Answer 1

multiply numerator and denominator by 8x what u get ?

Answer 2

you get 1 + 3/ 1 - 2/8x^2?

Answer 3

no...
\(\Huge \dfrac{1+3 \times (8x)}{1\times (8x)-2\times 8}\)

after multiplying by 8x i get that ^
could you think how ?

Answer 4

wait what happened to the 8x under the 1 in the numerator? does the 8x cancel that out?

Answer 5

yep
\(\Huge \dfrac{\dfrac{1}{\cancel {8x}}\times \cancel{8x}+3 \times (8x)}{1\times (8x)-2/ \cancel x\times 8\cancel x}\)

Answer 6

now got it ?

Answer 7

ohh I see okay one second

Answer 8

so 1 + (3 * 8x)/ 8x - 2/8?

Answer 9

denominator is 8x-2*8
not 2/8

Answer 10

Oh, I put 1 over the 8x okay now I get it

Answer 11

from which 8 can be factored out, so 8(x-8)

so, your final answer is just,
(1+24x)/[8(x-8)]
thats it!
any doubts?

Answer 12

No doubts! I'm just gonna write it out so I can remember what we did

Answer 13

sure :)

Answer 14

okay I have a question about the factoring, it's 8(x - 8) right? Or was it supposed to be 8(x - 2) or am I multiplying wrong?

Answer 15

oops, i mistyped it, sorry.
8x-2*8 = 8(x-2)
:)

Answer 16

Mmk I got it then ^_^ Thanks Hartnn!

Answer 17

welcome ^_^