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2 sin 2x cos x + 3 sin x=0 Find all solutions in interval (0,2pi)
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I have to run. Back soon...but, first step here would be to replace sin2x with 2sinxcosx When you get a cos^2(x) replace that with 1-sin^2(x) Then factor and set each factor = 0
ok so if u put in 2 sin(2*0(2+3SIN(0=0 so that's how u get zero
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