Question

Solve the equation. Identify any extraneous solutions.

Answer 1

a = 0

Answer 2

There is an extraneous solution that emerges from the standard procedure of initially squaring both sides.

Answer 3

Do you know how to square both sides?

Answer 4

0 and –2 are solutions of the original equation.
or
0 is a solution of the original equation. –2 is an extraneous solution.?

Answer 5

yes

Answer 6

yes what?

Answer 7

??????????????

Answer 8

a = 0
a = √2 √-a
-2a = a^2
-2a - a^2 = 0
-a(a + 2) = 0

So then you have:

a = 0 OR a + 2 = 0
(subtract 2 from both sides)

a = 0 OR a = -2

Answer 9

0 is the solution. -2 is the extraneous solution

Answer 10

Did I do my work correctly @BangkokGarrett? Just curious?

Answer 11

Ok thanks guys:) im closing this now but im opening another.

Answer 12

Okay:) and you are welcome!