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(12n^2*24n^1/4)^3
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what is inside parenthesis is (240n^(9/4). Now take that and raise it to the3rd power..so you multiply exponents, and you get 240n^(27/4)
(12n^2*24n^1/4)all to the ^3
do you get it???
\(\bf \Large {(12n^2\times 24n^{\frac{1}{4}})^3\implies (12\times 24n^{2+\frac{1}{4}})^3\\ \quad \\ (288n^{2+\frac{1}{4}=\frac{8+1}{4}=\frac{9}{4}})^3\implies 288^3(n^{\frac{9}{4}})^3\implies 288^3n^{\frac{27}{4}}}\)
thanks man
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