Question

finding the vertical and horizontal asymptote of r(x)=x/x^2-16

Answer 1

Horizontal Asymptote(s)..take limit of the function as x-----> infinity.

You get 0.

So y = 0 (the x-axis) is a horizontal asymptote.

Vertical Asymptote(s): x^2 - 16 = 0, x = 4 and x = -4

or lim x--->4 and x----> -4 of the function is infinite.


Result: One horizontal asymptote (y=0) and two vertical asymptotes (x=4 and x= -4)

Answer 2

if a rational function is proper, then_______is a horizontal asymptote

Answer 3

Your welcome.

Answer 4

thank you