Question

What are the solutions of 6x2 − x − 15 = 0?

x = 5 over 6, x = −3

x = −5 over 6, x = 3

x = 3 over 2, x = −5 over 3

x = −3 over 2, x =5 over 3

Answer 1

Use the quadratic formula.
\[x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
ax^2 + bx + c = 0
so your a b and c values are?