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Algebraic Expressions (x+3)(x-2) I'm not sure how to do this, would the answer be 3 x 2 = 6 , x + x = x^2 = 6x^2 ? And then (5x^3 + 15x) / (5x) = 3x^2 ??
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\[(5x^3 + 15x) \div (5x)\] Just incase people are confused with the second question.
\(\bf (x+3)(x-2)\implies x^2-2x+3x-6\\ \quad \\ \cfrac{5x^3 + 15x}{5x}\implies \cfrac{\cancel{5x}(x^2+3)}{\cancel{5x}}\)
FOIL METHOD .
aha im still trying to find out how he solved the first problem
just do FOIL as CGGURUMANJUNATH said, or just multiply the terms in one binomial, by the terms of the other
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