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Mathematics 23 Online
OpenStudy (anonymous):

Cosx+Tanx+Sinx-Sec^2x Simplify.

OpenStudy (anonymous):

Can you help me?

OpenStudy (anonymous):

Can you give me a couple of tips at least?

OpenStudy (jdoe0001):

I was gonna give you a Q-tip ....but tis ok =)

OpenStudy (anonymous):

Yes, give me a tip please!

OpenStudy (anonymous):

Can you guys give me some tips?

OpenStudy (jdoe0001):

invisible? hehe

OpenStudy (anonymous):

Ha ha! No for real! Can you give me some identities that would help me?

OpenStudy (anonymous):

K, thx!

OpenStudy (jdoe0001):

http://www.mathwords.com/t/trig_identities.htm for one.... but as Loser66 said...haven't found a simpler way about it

OpenStudy (anonymous):

@jdoe0001, thank you!

OpenStudy (jdoe0001):

|dw:1382480218589:dw|

OpenStudy (anonymous):

What?!

OpenStudy (jdoe0001):

ahemm GABI_J can you post a quick screenshot of the material?

OpenStudy (jdoe0001):

maybe there's something we're missing

OpenStudy (anonymous):

Screen shot?

OpenStudy (jdoe0001):

a quick picture of it, yes

OpenStudy (anonymous):

I don't know how to post pictures, but I think I did miss something, it is Sin^2x not Sinx Sorry about that.

OpenStudy (jdoe0001):

is the material on the screen?

OpenStudy (anonymous):

\[Cosx+Tanx+Sin^2x-Sec^2x\]

OpenStudy (anonymous):

( I am learning fast how to do everything here)

OpenStudy (anonymous):

I think I can do it, correct me if I am wrong, OK?

OpenStudy (jdoe0001):

wonder if you can still take the screenshot

OpenStudy (anonymous):

\[Cosx+Tanx+Sin^2x-Sec^2x\] \[Cosx+\frac{Sinx}{Cosx}+Sin^2x-\frac{1}{Cos^2x}\] I'll stop here to reply on that; I don't think so.

OpenStudy (anonymous):

to that... ooops

OpenStudy (anonymous):

No I can't do it, whatever forget about that....

OpenStudy (jdoe0001):

.... sooo... know how to take a screenshot?

OpenStudy (anonymous):

No

OpenStudy (anonymous):

Why do you care about that?

OpenStudy (jdoe0001):

well, just wondering if we were missing some extra info

OpenStudy (anonymous):

On this problem, nothing besides that it is Sin^2x and not Sinx That I said already.

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