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X^3+512=0 real or imaginary solution by factoring
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\(\bf \Large x^3+512=0\implies x^3=-512\implies x = \sqrt[3]{-512}\) what do you think?
it's better to use the sum of cubes factoring formula (so you can find the imaginary solutions as well)
hmm ohh yeah
x^3+512 = 0 x^3 + 8^3 = 0 (x+8)(x^2 - x*8 + 8^2) = 0 ... use the sum of cubes factoring formula (x+8)(x^2 - 8x + 64) = 0 I'll let you finish up
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