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Find the equation of the tangent line f(x) = x + (2/x); x = 4 y=?
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when x = 4, y = 4 + (2/4) = 9/2 The tangent line requires the slope at x = 4. The slope of f(x) is f ' (x) = 1- 2/(x^2)...quotient rule So at x = 4, the slope is 1 - 2/16 = 7/8 So the equation of the tangent line whose slope is 7/8 and passes through (4, 9/4) is y - (9/4) = 7/8(x - 4).
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