Question

Write an equation in standard form of the parabola that has the same shape as the graph of f(x)=-5x^2 , but with vertex at (-16,-11).
the equation is y=?

Answer 1

use y = a(x-h)^2 + k to set plug in the numbers of the given vertex, h=x and k=y

Answer 2

so, let(x) be y
y = -5x^2
turn it into this form
y = a(x-h)^2 + k
y = -5(x - (-16))^2 + (-11)
y = -5(x +16)^2 -11