The length of a poster is 7 in greater than the width. The perimeter is 114 in. Find the width and the length.

4w+14=114 is the equation.
I got 20 as the width. What's the length?

Question

The length of a poster is 7 in greater than the width. The perimeter is 114 in. Find the width and the length. 

4w+14=114 is the equation.
I got 20 as the width. What's the length?

ddcamp · Answer

"The length of a poster is 7 in greater than the width"

arbyj · Answer

@DDCamp So I multiply 7 x 20?

ddcamp · Answer

Let's look back at the equation you found for the area:
4w+14=114
How did you get that?

arbyj · Answer

My teacher had this answer bank set up for us and I assumed it would be this equation

ddcamp · Answer

l = w+7
P = 2w + 2l = 2w + 2(w+7) = 2w + 2w + 14 = 4w + 14

ddcamp · Answer

From that equation, we find w:
4w+14 = 114
4w = 100
w = 25

arbyj · Answer

Oh dang, I did the math wrong, I see

ddcamp · Answer

Then we find l from the original problem. The first line says that the length is seven inches longer than the width, or:
l = w+ 7
l = 25+7
l = 32

arbyj · Answer

Oh ok