Question

find three consecutive odd integers such that the sum of all three is 42 less than the product of the larger two. NEED HELP???

Answer 1

Let x be an odd integer
The, the next consecutive odd integer is x + 2
And, the next is x + 4.

Convert the words from the problem into symbols.

Answer 2

the sum of all three is 42 less than the product of the larger two.

x + x + 2 + x + 4 = (x + 2)*(x + 4) -42

x + x + 2 + x + 4 = (x + 2)*(x + 4) - 42


@waffles56 The first task is to solve the above equation for x.

Answer 3

THANK YOU @Directrix

Answer 4

You are welcome. Did you solve for the numbers?

Answer 5

yes i got 5,7,9