Question

expand (sin2x)^2

Answer 1

\[LARGE (sin2x)^2=(2sinxcosx)^2=4sin^2xcos^2x\]

Answer 2

=(2sinxcosx)^2
=4*[(1-cos2x)/2]*[(1+cos2x)/2]
=(1-cos2x)*(1+cos2x)
=1-(co2x)^2

Answer 3

=sin(2x)^2

Answer 4

we come back ,haha

Answer 5

Taylor Expansion for sin^2(2x)?

(sin2x)^2 = (2x - (8x^3)/3! + (32x^5)/5! . . .)^2
= (2x - (8x^3)/3! + (32x^5)/5! . . . )(2x - (8x^3)/3! + (32x^5)/5! . . . )