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If the cos 30° = square root of 3/2 , then the sin 60° = _____.
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\[\sin \theta=\cos \left( 90-\theta \right) \] \[put \theta=60 \]
so its 0 ?
How ?
here is the triangle |dw:1382555588323:dw| what do you think sin(60) is ?
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