Solve the following system of equations.

2x + 2y + z = 10
3x – y + 3z = 10
2x + 3y – 2z = 6

(2, 2, 2)

(–2, 2, 2)

(2, –2, 2)

(2, 2, –2)

Question

Solve the following system of equations. 

2x + 2y + z = 10 
3x – y + 3z = 10 
2x + 3y – 2z = 6

 (2, 2, 2)

 (–2, 2, 2)

 (2, –2, 2)

 (2, 2, –2)

anonymous · Answer

im not sure if im doing this right im about to put up my work in a sec

abbie · Answer

can you post this in the mathematics section?

anonymous · Answer

lol omg i didnt even notice that

abbie · Answer

look for examples

abbie · Answer

NP

abbie · Answer

heres an example I found 
(1) 2x + 3y - z = 4
(2) 3x + 2y + 2z = 6
(3) 4x - y + 3z = 5
multiply (3) by 2
8x - 2y + 6z = 10
(2) 3x + 2y + 2z = 6
add them
11x + 8z = 16
multiply (3) by 3
(3) 12x - 3y + 9z = 15
(1) 2x + 3y - z = 4
add them
14x + 8z = 19
11x + 8z = 16
subtract
14x + 8z = 19
-11x -8z = -16
3x = 3
x = 1
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11x + 8z = 16
11*1 +8z = 16
8z = 5
z = 5/8
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