Question

5x^2 -13x-6 I need to find the vertex, i think i have found x but I need to find Y, please help!

Answer 1

I found x to equal 13/10

Answer 2

for a parabola equation of that type, that is \(\bf ax^2+bx+c\) you can find the vertex at \(\bf \left(-\cfrac{b}{2a}\quad ,\quad c-\cfrac{b^2}{4a}\right)\)

Answer 3

thank you!

Answer 4

yw