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Mathematics 15 Online
OpenStudy (anonymous):

Which is the completely factored form of x^6-64y^3?

OpenStudy (campbell_st):

well its really the difference of 2 cubes \[(x^2)^3 - (4y)^3\] so using a^3 - b^3 = (a - b)(a^2 + ab + b^2) you should be able to factor it.

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