Question

x + 2y = 50
-2x + 3y = 40
5x + 5y +5z = 300

Answer 1

(-10, -20, -30)
(10, 20 ,30)
(10,20, -30)
(10, -20, 30)
What would be the answer?

Answer 2

@Mertsj could you please help me?

Answer 3

@Hero would it be a problem for you?

Answer 4

@ganeshie8 ??

Answer 5

im begging

Answer 6

Divide the both sides of 5x + 5y + 5z = 300 by 5 to get:

x + y + z = 60


So now you have:

x + 2y = 50
-2x + 3y = 40
x + y + z = 60

Pair the 1st and second equations together:

x + 2y = 50
-2x + 3y = 40

x + 2y = 50 by 2 to get:
2x + 4y = 100
-2x + 3y = 40

Then combine them together to get:
7y = 140
y = 20

Since y = 20, use that to find x:
x + 2y = 50
x + 2(20) = 50
x + 40 = 50
x = 50 - 40
x = 10

Since x =10, y = 20, find z:

x + y + z = 60
10 + 20 + z = 60
30 + z = 60
z = 60 - 30
z = 30

So (x,y,z) = (10, 20, 30)