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Someone please help! Solve the open sentence. –1 ≤ n + 2 ≤ 6 n ≥ 3 and n ≤ –2 n ≤ –3 and n ≤ 2 n ≤ 1 and n ≤ 6 n ≥ –3 and n ≤ 4 2.Solve the open sentence. 6 < 3b OR 3b + 12 < 9 b < –1 OR b > –6 b < –1 OR b < 3 b < 2 OR b > –3 b > 2 OR b < –1 3. A compound inequality is graphed, and its graph consists of all real numbers. Which open sentence could have resulted in this solution set? r < 6 or r > – 4 r < 6 or r < – 4 r > 6 or r < – 4 r > 6 or r > – 4
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