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For what values of t on the interval [2pie, 2pie] does the graph of h(t) = tan t have vertical asymptotes?
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From the graph of tan t, it will have vertical asymptotes at t = -3pi/2, -pi/2, pi/2, 3pi/2
at 4 places on the closed interval [ - 2pi, 2 pi]
You'll want where tanx is undefined... tan x is \[\Large \frac{ \sin x }{\cos x }\]it's undefined where cosx = 0 since that means dividing by zero. Can you find where cosx=0? (between -2pi and 2pi)
Cosx = 0 for \[\Large x = \frac{ \pi }{ 2 } \pm \pi\]
x = pi/2 +/- n pi, where n is an integer
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Yeah, i forgot the k or n, oops
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