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OpenStudy (anonymous):
Hey, can someone please explain how to differentiate 3rootx times e^x plz?
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OpenStudy (anonymous):
\[(fg)'=f'g+g'f\] with \[f(x)=\sqrt{x}, f'(x)=\frac{1}{2\sqrt{x}}, g(x)=e^x, g'(x)=e^x\]
OpenStudy (anonymous):
my teacher told us that the answer was (1+3x)e^x/3(3rootx^2) ... Not sure how he gets this?
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