Mathematics
7 Online
OpenStudy (anonymous):
if sinh x = 15/8
find the values of the other hyperbolic functions at x.
cosh x =
tanh x =
csch x =
sech x =
coth x =
how do I do this ??
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OpenStudy (anonymous):
try reading here
OpenStudy (anonymous):
read what ??
OpenStudy (anonymous):
cosh^2(x) - sinh^2(x) = 1
OpenStudy (anonymous):
subtitusi sinh = 15/8 to that equation
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OpenStudy (anonymous):
does 1.301708279 = cosh ??
OpenStudy (anonymous):
can you do that?
OpenStudy (anonymous):
what do you mean by that ?
OpenStudy (anonymous):
subtitusi, sorry the network is bad
OpenStudy (anonymous):
cosh x = 17/8
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OpenStudy (anonymous):
cosh^2(x)-(15/8)^2=1
cosh^2(x)=1+(15/8)^2
i am i on the right track ??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
cos=\[\sqrt{1+(15/8)^2}\]
OpenStudy (anonymous):
yea it does
OpenStudy (anonymous):
ok so from here how do i find the rest ?
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OpenStudy (anonymous):
this ??
OpenStudy (anonymous):
(15/8)^2 = 15^2/8^2
OpenStudy (anonymous):
what does that mean ?
OpenStudy (anonymous):
\[\sqrt{1+\ \left( \frac{ 15 }{ 8 } \right)^2}\]
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OpenStudy (anonymous):
\[\sqrt{1+\frac{ 15^2 }{ 8^2 }}\]
OpenStudy (anonymous):
yea that's 17/8
OpenStudy (anonymous):
\[\sqrt{1+\frac{ 225 }{ 64 }}\]
OpenStudy (anonymous):
yes that right
OpenStudy (anonymous):
how do we find tanh (x) form there ?
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OpenStudy (anonymous):
tanh x = sinh x / cosh x
OpenStudy (anonymous):
(15/8)/(17/8)= tanh(x)
OpenStudy (anonymous):
yes, simplify
OpenStudy (anonymous):
csch x = 1/sinh x
sech x = 1/ cosh x
coth x = 1 / tanh x
OpenStudy (anonymous):
So csch is 1/(15/8)
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OpenStudy (anonymous):
yes, but please simplify become 8/15
OpenStudy (anonymous):
ok I understand this now than you soo much !!!!
OpenStudy (anonymous):
thank you soo much !
OpenStudy (anonymous):
oks