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f(x) = 2x g(x) = 3x³ f(x)/ g(x) = ?
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\[\frac{ 2x }{ 3x^3 }=\frac{ 2 }{ 3 }x^-2=\frac{ 2 }{ 3x^2 }\]
Because it's a -2 it goes on the bottom?
because x is a -2*
yes and for for any base with a negative exponent.. its value its a fraction
\[x^-1=\frac{ 1 }{ x }\]
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Okay but when it goes on the bottom it becomes a positive again then?
Yes you are right.
Thank you
you are most welcomed
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