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r is actually raised to the power (n-1), so there are only 2 variables multiplying.
i think tht the answer is D
@Starr_Dynasty If you have read my explanation, you would know it is not, because (n - 1) is the power of r.
\(\Large \bf ar^{n-1}\implies a\cdot r^{n-1}\)
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so the answer is B
@jdoe0001 @tyteen4a03 oh the answer is A
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